Question

solve the following equations 2(n-2)-5(n-5)=4(n-8)-2(n-2)​

Answer 1

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Solve the following equation : 2(n-2)-5(n-5)=4(n-8)-2(n-2)

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2(n-2)-5(n-5) = 4(n-8)-2(n-2)

2n-4-5n+25 = 4n-32-2n+4

2n-5n-4+25 = 4n-2n-32+4

-3n+21 = 2n-28

21+28 = 2n+3n

5n = 49

n = 49/5

Or

n = 9.8

Answer 2

Step-by-step explanation:

2n-4-5n+25=4n-32-2n+4

-3n+21=2n-28

21+28=2n+3n

29=5n

5n=29

n=49/5

n=9.8