Question

Solve the following equations :
(a) 2x + 1 = 5
(b) 6y - 5 = 19
(c) 3+4y= -10
(d) 2/3p =6
(e) 5y + 10 = 4y - 10
(f) 1/2x+3=5
(g) 3(x+1)=6
(h) 4(x-2)= -8
(I) 3x +8=5x+2
(j) 1/3x+11=14
(k) x-5/4 =3
(l) z+3/4=17

PLEASE GIVE ME ANS. FAST ➡ ​

Answer 1

Answer:

solution

Step-by-step explanation:

a x=2

b)y=4

c)y=3

Answer 2

Step-by-step explanation:

(a) 2x + 1 = 5   ⇒ 2x = 5 - 1  ⇒ 2x = 4  ⇒ x = 4÷2  ⇒ x = 2

(b) 6y - 5 = 19   ⇒ 6y = 19 + 5  ⇒ 6y = 24  ⇒ y = 24 ÷ 6  ⇒ y = 4

(c) 3+4y= -10   ⇒ 4y = -10 - 3  ⇒ 4y = -13  ⇒ y = -13 ÷ 4  ⇒ y = $-3\frac{1}{4}$

(d) 2/3p =6   ⇒ p = (6 * 3) ÷ 2  ⇒ p = 18 ÷ 2  ⇒ p = 9

(e) 5y + 10 = 4y - 10   ⇒ 5y - 4y = -10 - 10 ⇒  y = -20

(f) 1/2x+3=5   ⇒  $\frac{x}{2}$ = 5 - 3  ⇒ $\frac{x}{2}$ = 2  ⇒ x = 2 * 2  ⇒ x = 4

(g) 3(x+1)=6   ⇒  3x + 3 = 6  ⇒ 3x = 6 - 3  ⇒ 3x = 3  ⇒ x = 3 ÷ 3  ⇒ x = 1

(h) 4(x-2)= -8   ⇒ 4x - 8 = -8  ⇒ 4x = -8 + 8  ⇒ 4x = 0  ⇒ x = 0

(I) 3x +8=5x+2  ⇒ 5x - 3x = 8 - 2  ⇒ 2x = 6  ⇒ x = 6 ÷ 2  ⇒ x = 4

(j) 1/3x+11=14  ⇒ $\frac{x}{3}$ = 14 - 11  ⇒ $\frac{x}{3}$ = 3  ⇒ x = 3 * 3  ⇒ x = 9

(k) x-5/4 =3   ⇒ x = (3 * 4) ÷ 5  ⇒ x = 12 ÷ 5  ⇒ x = $\frac{12}{5}$

(l) z+3/4=17 ⇒ z = 17 - $\frac{3}{4}$  ⇒ z = $\frac{68 - 3} {4}$  ⇒ z = $\frac{65}{4}$  ⇒ z = $16\frac{1}{4}$