Question

solve the following pair of linear equation by any method (a)- x+2y-3=0;3x-2y+7=0

Answer 1

★ Answer :

x + 2y - 3 = 0 ........(1)

3x - 2y + 7 = 0 .........(2)

→ From equation 1.

⇒x + 2y = 3

⇒x = 3 - 2y

→ Put value of x in equation (2).

⇒3(3 - 2y) - 2y + 7 = 0

⇒9 - 6y - 2y + 7 = 0

⇒-8y + 16 = 0

⇒-8y = -16

⇒8y = 16

⇒y = 16/8

⇒y = 2

$\rule{150}{2}$

Now,

→ Put value of y in equation (1).

⇒x + 2(2) = 3

⇒x + 4 = 3

⇒x = 3 - 4

⇒x = -1

Answer 2

Answer:

4x + y – 6 = 0

⇒ y = 6 – 4x

Value of y put in eqn. (i)

3x + 2y – 7 = 0

⇒ 3x + 2(6 – 4x) – 7 = 0

⇒ 3x + 12 – 8x – 7 = 0

⇒ 5 – 5x = 0

⇒ 5x = 5

x = 1

Substitute the value of x in eq (ii) to get value of y,

4x + y – 6 = 0

⇒ 4(1) + y – 6 = 0

⇒ 4 + y – 6 = 0

⇒ y – 2 = 0

y = 2

Hence, values of x and y are 1 and 2 respectively

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