Question

solve the following pair of linear equation by elimination method 10x+3y=75 ,6x-5y=11

Answer 1

I had uploaded the answer.hope it helps you.

Answer 2

$Given \:pair \:of \: linear \:equations \\</p><p>10x + 3y = 75 \: ---(1) \\and \\6x-5y = 11 \: ---(2)$

$Multiplying \:equation \: (1) \:by \: 5 \:and \\equation \: (2) \:by \: 3 , \: we \:get$

$50x + 15y = 375 \: --(3) \\18x - 15y = 33 \: --(4)$

/* Adding equations (3) and (4) ,we get */

$50x + 15y + 18x - 15y = 375 + 33$

$\implies 68x = 408$

$\implies x = \frac{408}{68}$

$\implies x = 6$

/* Put x = 6 in equation (1), we get */

$10\times 6 + 3y = 75$

$\implies 60 + 3y = 75$

/* Dividing each term by 3 , we get */

$\implies 20 + y = 25$

$\implies y = 25 - 20$

$\implies y = 5$

Therefore.,

$\red { x = 6 \: and \: y = 5 }$

•••♪