Question

Solve the following pair of linear equations by reducing them to a pair of linear equations= 4/X+3y=14
3/x-4y= 23

Answer 1

aloha user!!

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we are given two equations:

4/x + 3y = 14
3/x - 4y = 23


now for reducing them to a pair of linear equations we are going to write

1/x as A and y as B

so, the equations:

4A + 3B = 14
3A - 4B = 23

we can now use elimination or substitution or even cross multiplication.
here i have used elimination because it is easy for me and i hope it would be for you too.


so,

multiplying the second equation by 4 and the first equation by 3 we get:

3 (4A + 3B = 14)
4 ( 3A - 4B = 23 )

↡

12A + 9B = 42
12A - 16B =92
___________
-     +             -
___________
        25B = -50


B = -50/ 25
B = -2 = y

Putting the value of B in any of the equation we will get the value of A :

12A + 9B = 42
12A + 9 ( -2 ) = 42
12A - 18 = 42
12A = 42 + 18
12A = 60
A = 60/ 12
A = 5

So,

1/x = 5
x = 1/5 
y = -2 



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hope it helps !!

good life !!