Solve the following pair of linear equations by substitution method :
2x + 3y = −9 and 3x −7y = 44
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2x + 3y = −9 ( equation 1 )
3x −7y = 44 ( equation 2)
firstly multiply the whole equation 1 with 3 and equation 2 with 2 we get,
6x + 9y = -27
6x - 14y = 88
now, simply substract equation 2 from equation 1 we get
25y = -115
y = -115/25
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