Question

Solve the following problem graphically: Maximize Z = 3x + 4y subject to x + y ≤ 450 2x + y≤ 600 where x1, x2≥ 0

Answer 1

Given :   x + y ≤ 450 2x + y≤ 600 where x ,y≥ 0

To find : Maximize Z = 3x + 4y

Solution:

x , y ≥ 0

x + y ≤ 450

2x + y ≤ 600

( 0 , 450 ) ( 300 , 0)  , ( 150 , 300)  are the point

z = 3x + 4y

( 0 , 450 )

=> z = 0+ 4 * 450 = 1800

( 300 ,  0 )

=> z = 3*300+ 0 = 900

( 150 , 300)

=> z = 3*150+ 4*300 = 1650

( 0 , 450 )

x = 0

y = 450 will give maximum profit

= 1800

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