solve the following quadratic equation 3-x=3x^2
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3-x=3x^2
3x^2+x-3=0
by quadratic formula is
-b+-√b^2-4ac÷2a
b=1 a=3 c=-3
-1+-√1^2-4×3×(-3)÷2×3
-1+-√37÷6
value of x are √37-1÷6 and-1-√37÷6
3x^2+x-3=0
by quadratic formula is
-b+-√b^2-4ac÷2a
b=1 a=3 c=-3
-1+-√1^2-4×3×(-3)÷2×3
-1+-√37÷6
value of x are √37-1÷6 and-1-√37÷6
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