Question

Solve the following quadratic equation: 4x² - 4ax + (a² - b²) = 0.

Answer 1

Given: 4x² - 4ax + (a² - b²) = 0.

Here in this equation, constant term = (a² - b²) = (a+b)(a-b)
Coefficient of middle term= - 4a

Also, Coefficient of the middle term= -[2(a+b)+2(a+b)]

4x² - 4ax + (a² - b²) = 0.
4x² -[2(a+b)+2(a-b)]x + (a+b)(a-b)= 0
4x² - 2(a+b)x - 2(a-b)x + (a+b)(a-b)= 0
[4x² - 2(a+b)x ] - [ 2(a- b)x + (a+b)(a-b)]= 0
2x [ 2x-(a+b)] -(a-b)[2x -  (a+b)]
[2x -  (a+b)] [2x-(a-b)]= 0
[2x -  (a+b)] = 0  or  [2x-(a-b)]= 0

2x = a + b   or    2x = a-b

x =( a+b)/2 or  x= (a-b)/2

HOPE THIS WILL HELP YOU...

Answer 2

HEYA MATE!!!

YOUR SOLUTION IS IN THE ATTACHMENT..

#KEVIN

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