Math, asked by Rachit6453, 9 months ago

Solve the following quadratic equation by factorisation y2-8y-9=0

Answers

Answered by deep200593
7

Answer:

9

Step-by-step explanation:

y²-8y-9=0

=>y²-(9-1)y-9=0

=>y²-9y+y-9=0

=>y(y-9)+1(y-9)=0

=>(y+1)(y-9)=0

As it is multiplication then on of the number will be 0

Let (y-9) be 0

Then,

y-9=0

=>y=9

Hope it is clear...

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Answered by kanusoftdrinks
1

Answer:

y²-(9-1)y-9

y²-9y+y-9

y(y-9)+1(y-9)

(y+1)(y-9)

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