Solve the following quadratic equation by factorisation y2-8y-9=0
Answers
Answered by
7
Answer:
9
Step-by-step explanation:
y²-8y-9=0
=>y²-(9-1)y-9=0
=>y²-9y+y-9=0
=>y(y-9)+1(y-9)=0
=>(y+1)(y-9)=0
As it is multiplication then on of the number will be 0
Let (y-9) be 0
Then,
y-9=0
=>y=9
Hope it is clear...
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Answered by
1
Answer:
y²-(9-1)y-9
y²-9y+y-9
y(y-9)+1(y-9)
(y+1)(y-9)
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