solve the following quadratic equations by factorization
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QUESTION (31) :- x^2+[a+1/a]x+=0
SOLUTION:-
=》 x^2+[1+1]x+1=0
=》 x^2+(2)x+1=0
=》 x^2+2x+1=0
TREE METHOD :-
x^2
/ \
/ \
factors= 1x , 1x
\ /
\ /
2x
=》 x^2+1x+1x+1
lets take out common factors
=》 x(x+1)+1(x+1)
=》(x+1)(x+1)
Therefore x+1 is a factor
x+1 = 0
x=0-1
x=-1
SOLUTION:-
=》 x^2+[1+1]x+1=0
=》 x^2+(2)x+1=0
=》 x^2+2x+1=0
TREE METHOD :-
x^2
/ \
/ \
factors= 1x , 1x
\ /
\ /
2x
=》 x^2+1x+1x+1
lets take out common factors
=》 x(x+1)+1(x+1)
=》(x+1)(x+1)
Therefore x+1 is a factor
x+1 = 0
x=0-1
x=-1
taranggupta:
thanku
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