Question

solve the following question using quadratic formula y^2-14y-12=0​

Answer 1

Answer:

$7±2 \sqrt{61}$

Step-by-step explanation:

${y}^{2} - 14y - 12 = 0$

$roots \: are$

$\frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$= \frac{14± \sqrt{196 + 48} }{2}$

$= \frac{14± \sqrt{244} }{2}$

$= \frac{14±4 \sqrt{61} }{2}$

ꁝꏂꋊꉔꏂ ꋪꄲꄲ꓄ꇙ ꋬꋪꏂ

$7±2 \sqrt{61}$