Math, asked by quantumgamer82, 1 year ago

solve the following simultaneous linear equation 3 - 2 (3x + 4y) = x, x-3/4-y-4/5=21/10​

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Answered by knjroopa
22

Step-by-step explanation:

Given solve the following simultaneous linear equation 3 - 2 (3x + 4y) = x, x-3/4-y-4/5=21/10​

  • Given simultaneous equation to solve for x and y
  • So 3 – 2(3x + 4y) = x
  • So x – 3 / 4 – y – 4 / 5 = 2 1/10
  • Solving we get
  • 3 – 6x – 8y = x
  • 7x + 8y – 3 = 0
  • So x – 3 / 4 – y – 4 / 5 = 21 / 10
  • 5(x – 3) – 4(y – 4) / 20 = 21/10
  • 5x – 15 – 4y + 16 = 42
  • 5x – 4y – 41 = 0
  • Now we have both the equations
  •                    5x – 4y – 41 = 0
  •                    7x + 8y – 3 = 0
  •     Multiply 1st equation by 7 and 2nd by 5 we get
  •                     35x – 28y -287
  •                     35x + 40y – 15  
  • Subtracting we get
  •               So    - 68 y = 272
  •              Or y = - 272 / 68
  •               Or y = - 4
  •           Now 7x + 8(-4) – 3 = 0
  •                     7x – 35 = 0
  •                      7x = 35
  •                  Or x = 5

Reference link will be

https://brainly.in/question/8694723

Answered by prishaa142709
0

Answer

answer is in the photo graph

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