solve the following simultaneous linear equation 3 - 2 (3x + 4y) = x, x-3/4-y-4/5=21/10
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Given solve the following simultaneous linear equation 3 - 2 (3x + 4y) = x, x-3/4-y-4/5=21/10
- Given simultaneous equation to solve for x and y
- So 3 – 2(3x + 4y) = x
- So x – 3 / 4 – y – 4 / 5 = 2 1/10
- Solving we get
- 3 – 6x – 8y = x
- 7x + 8y – 3 = 0
- So x – 3 / 4 – y – 4 / 5 = 21 / 10
- 5(x – 3) – 4(y – 4) / 20 = 21/10
- 5x – 15 – 4y + 16 = 42
- 5x – 4y – 41 = 0
- Now we have both the equations
- 5x – 4y – 41 = 0
- 7x + 8y – 3 = 0
- Multiply 1st equation by 7 and 2nd by 5 we get
- 35x – 28y -287
- 35x + 40y – 15
- Subtracting we get
- So - 68 y = 272
- Or y = - 272 / 68
- Or y = - 4
- Now 7x + 8(-4) – 3 = 0
- 7x – 35 = 0
- 7x = 35
- Or x = 5
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https://brainly.in/question/8694723
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answer is in the photo graph
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