tan(π/4+theta)/tan(π/4-theta)=(1+tan theta/1-tan theta)^2
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tan(π/4+theta)/tan(π/4-theta)=(1+tan theta/1-tan theta)^2
Step-by-step explanation:
left side = tan ( π 4 − θ )
Expand using the above addition formula for
tan ( a − b )
⇒
tan ( π- 4 ) tan θ /1 + tan ( π 4 ) tan θ
Reminder
tan ( π -4 ) = 1
⇒ 1 − tan θ 1 + tan θ =right side
→ verified
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