Question

Solve the following system of equations:
21/x 47/y = 110
47/x + 21/y = 162, x, y ≠ 0

Answer 1

x = 1/3   &  y = 1    for  following system of equations:  21/x 47/y = 110  , 47/x + 21/y = 162,

Step-by-step explanation:

21/x 47/y = 110

47/x + 21/y = 162, x, y ≠ 0

let say 1/x = u   & 1/y = v

then

21u  + 47v = 110    

47u  + 21v = 162

adding both

68u + 68v = 272

=> u + v = 4

on subtracting 1st from 2nd

26 u - 26v = 52

=> u - v = 2

 u + v = 4

  u -v = 2

adding both 2u = 6

=> u = 3

& v = 1

x = 1/3    y = 1

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