Question

Solve the following system of linear equation graphically 2x+y+6=0, 3x-2y-12=0 Also find the vertices of vertices of the triangle formed by the lines representing the above equation and x-axis​

Answer 1

Answer:

Step-by-step explanation:

Given Pair of equations

2x+y+6=0..........(1)

3x-2y-12=0 ......(2)

2x+y+6=0

If x=1,

2(1)+y+6=0

y=(-8)

If x=0,

2(0)+y+6=0

y=(-6)

3x-2y-12=0

If x= 2,

3(2) -2y -12=0

y=(-3)

If x=0,

3(0)-2y-12=0

y=(-6)

Now Draw the graph and lines. They intersect and form vertices with each other and x-axis.The vertices are :

A(0,-3)

B(0,-4)

C(0,-6)

Area of Δ = 1/2 x b x h

                = 1/2 x 7 x 6

                = 21 sq. units

*method is correct, answer may differ

The graph will look as follows :