solve the following system of linear equations graphically 2x-y-4=0,x+y+1=0
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Answered by
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multiply x+y+1=0 with 2
⇒ the 2 equations are 2x-y-4=0 and 2x+2y+2=0
subtract 2 equation from first equation
⇒-3y-6=0
⇒-3y=6
⇒y=6/-3
⇒y=-2
substitute y = -2 in the equation x+y+1=0
⇒x-2+1=0
⇒x=1
⇒ the 2 equations are 2x-y-4=0 and 2x+2y+2=0
subtract 2 equation from first equation
⇒-3y-6=0
⇒-3y=6
⇒y=6/-3
⇒y=-2
substitute y = -2 in the equation x+y+1=0
⇒x-2+1=0
⇒x=1
Answered by
1
2x-y=0
x-y=0
x+y+1=0
x+y=0-1
x-y= –1
x-y=0
x+y+1=0
x+y=0-1
x-y= –1
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