Math, asked by TheFlip, 6 months ago

Solve the following system of linear equations in three variables
x+y+z=24 ,5x+3y+z=56 , x+y=z.

Answers

Answered by clarkjaypenas42
1

Answer:

x+y+z-24.5x+3y+z=56x+y-z

  1. cancel equal terms

x+z-24.5x+3y+2=56x-z

  1. collect like terms

-23.5x+z+3y+z=56x-z

  1. move the terms

-23.5x-56x=-z-z-3y-z

  1. collect like terms

-79.5x=2x-3y-z

  1. divide both sides

x=4/159z+yx2/53+4/159

  1. write in parametric form

x=4/159z+yx2/53+4/159,y

  1. solution

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