Solve the following systems by Elmination by Substitution method.
2x+3y=5 ; 3x+2y=10
Answer x= 4 , y= -1
(class 10th)
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solution
multiply 1 by 3 & 2 by 2, then we get.
6x+ 9y= 15.... (3)
& 6x+ 4y= 20....(4)
Now, subtract it.
=> 5y= -5
=> ✔y= -1✔
now, putting the value of y in 2.we get
=>3x+ 2(-1)= 10
=> 3x= 12
=> ✔x= 4✔
___________
hope it helps☺✌✌
multiply 1 by 3 & 2 by 2, then we get.
6x+ 9y= 15.... (3)
& 6x+ 4y= 20....(4)
Now, subtract it.
=> 5y= -5
=> ✔y= -1✔
now, putting the value of y in 2.we get
=>3x+ 2(-1)= 10
=> 3x= 12
=> ✔x= 4✔
___________
hope it helps☺✌✌
Answered by
1
there it is..................
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