Question

Solve the following systems of equations:
$x+\frac{y}{2} = 4$
$\frac{x}{3}+2y= 5$

Answer 1

Given :  

x + y/2 = 4 …………...( 1 )

x/3 + 2y = 5…………...( 2 )

Elimination method is used to solve this Linear pair of Equations:

On multiplying equation (1) by 4 :  

4x + 4y/2 = 16

4x + 2y = 16………..(3)

On subtracting equations (2) from eq  (3) :

4x + 2y = 16

x/3 + 2y = 5

(-)  (-)  (-)

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4x - x/3  = 11

(4x × 3 - x)/3 = 11

(12x - x)/3 = 11

11x = 11 × 3

11x = 33

x = 33/11

x = 3

On putting x = 3 in eq (2)  we get :

x/3 + 2y = 5

3/3 + 2y = 5

1 + 2y = 5

2y = 5 - 1

2y = 4

y = 4/2

y = 2

Hence, the value of the given system of equation is x = 3  and y = 2.

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Answer 2

Answer:

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