Question

Solve the given quadratic equation:
ix² - 4x - 4i = 0

Answer 1

To solve this equation, let us apply Quadratic formula

$i{x}^{2} -4x -4i= 0 \\ \\ a = i\\ \\ b = -4\\ \\ c =-4i\\ \\ x_{1,2} = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_{1,2} = \frac{ 4 ± \sqrt{ {(-4)}^{2} - 4(i)(-4i)} }{2 \times i} \\ \\ x_{1,2} = \frac{ 4± \sqrt{16 +16i^{2}} }{2i} \\ \\ x_{1,2} = \frac{ 4±\sqrt{16-16} }{2i} \\ \\x_{1,2}= \frac{ 4±0}{2i}\\ \\x_{1,2} = \frac{ 2}{i} \times \frac{i}{i}\\ \\ \\x_{1,2} = \frac{ 2i}{i^{2}} \\\\x_{1} =-2i\\ \\x_{2} =-2i$
Hope it helps you.

Answer 2

Answer:   -2i

Step-by-step explanation:

eq. is ix^2-4x-4i

solution :

comparing above eq with ; ax^2 +bx+c=0

a= i , b = -4 , c= -4i

:. b^2 - 4ac

=(-4)^2   -  4 X i X ( -4i )

=16 - ( -16 ) i^2

=16 + 16 x ( -1) - - - - - - -(  i^2  =  -1)

=16-16

= 0

             

x=  -b + √b^2 -4a÷2a       or      -b  -√b^2-4ac÷2a

     -(-4) +√0÷2i                or      -(-4) - √0÷2a

      4+0÷2i                        or       4-o÷2i

     2 divided by  i                2 divided by  i  

    2 multiply by  i upon i Xi

   2i  upon i^2

   =2i upon -1

=-2i