Question

Solve the given quadratic equation X2-root2x-12

Answer 1

${x}^{2} - \sqrt{2} x - 12 \\ = {x}^{2} - 3 \sqrt{2} x + 2 \sqrt{2} x - 12 \\ = x(x - 3 \sqrt{2} ) + 2 \sqrt{2} (x - 3 \sqrt{2} ) \\ = (x - 3 \sqrt{2} )(x + 2 \sqrt{2} ) \\ x = + 3 \sqrt{2} \\ x = - 2 \sqrt{2}$
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Answer 2

x²-√2x-12=0

x²-(3√2x-2√2x)-12=0

x²-3√2x+2√2x-12=0

x(x-3√2)+2√2(x-3√2)

(x+2√2)(x-3√2)

x= -2√2

and +3√2