Question

solve the given question please find accelration contact force net force​

Answer 1

Answer:

★ Acceleration = 3 * 2 = 6m/sec²

★ Contact Force = 6 - 6 = 0N

Answer 2

Explanation:

Let us first calculate the limitation and kinetic friction between various surfaces. Between 3 kg and ground:

fl1=fk1=μ1(2+3)g=0.1×5g=5N

Between 2 kg and 3 kg: 

fl2=fk2=μ2g=0.2×2g=4N

Let us first assume that both blocks move together with common accleration a.

a=2+35+10−fk1⇒a=515−5=2ms2

Now let us see how much friction force is required between 2kg and 3kg for common acceleration a.

5−f2=2a⇒5−f2=2×2⇒f2=1N

Since f2<fl2,

1. Both blocks will move together with common accelerationa=2ms−2

2. Friction between 2kg and 3 kg =f2 = 1N Friction between 3 kg and ground = fk1= 5N