Math, asked by RaviRaj615, 1 year ago

Solve the inequality,
4x + 3 < 5x + 7

Answers

Answered by nrana
10

4x+3<5x+7

4x+3-3<5x+7-3

4x<5x+4

4x-5x<5x-5x+4

-x<4

x>-4

Answered by AnIntrovert
45

Given that, 4x + 3 < 5x + 7

Now by subtracting 7 from both the sides, we get

4x + 3 – 7 < 5x + 7 – 7

The above inequality becomes,

4x – 4 < 5x

Again by subtracting 4x from both the sides,

4x – 4 – 4x < 5x – 4x

x > – 4

∴The solutions of the given inequality are defined by all the real numbers greater than -4.

Required solution set is (-4, ∞)

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