Solve the pair of equations by reducing them to a pair of linear equations.
10/(x + y) + 2/(x - y) = 4
15/(x + y) - 5/(x - y) = -2
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Hi ,
Let a = 1/( x + y ) ,
b = 1/( x - y ) ;
10/( x + y ) + 2/( x - y ) = 4
=> 10a + 2b = 4
=> 5a + b = 2
=> b = 2 - 5a ----( 1 )
15/( x + y ) - 5/( x - y ) = -2
=> 15a - 5b = -2---( 2 )
Substitute ( 1 ) in equation ( 2 ) , we get
15a - 5( 2 - 5a ) = -2
15a - 10 + 25a = -2
40a = -2 + 10
a = 8/40
a = 1/5
Substitute a = 1/5 in equation ( 1 )
we get,
b = 2 - 5 × ( 1/5 )
b = 2 - 1
b = 1
Therefore ,
1/( x + y ) = a = 1/5=> x + y = 5 -( 3)
1/( x - y ) = b = 1/1=> x - y = 1/1 --( 4 )
add equations ( 3 ) and ( 4 ), we get
2x = 5 + 1
2x = 6
x = 3
Substitute x = 3 in equation ( 3 ),
3 + y = 5
y = 5 - 3
y = 2
Therefore ,
x = 3
y = 2
I hope this helps you.
: )
Let a = 1/( x + y ) ,
b = 1/( x - y ) ;
10/( x + y ) + 2/( x - y ) = 4
=> 10a + 2b = 4
=> 5a + b = 2
=> b = 2 - 5a ----( 1 )
15/( x + y ) - 5/( x - y ) = -2
=> 15a - 5b = -2---( 2 )
Substitute ( 1 ) in equation ( 2 ) , we get
15a - 5( 2 - 5a ) = -2
15a - 10 + 25a = -2
40a = -2 + 10
a = 8/40
a = 1/5
Substitute a = 1/5 in equation ( 1 )
we get,
b = 2 - 5 × ( 1/5 )
b = 2 - 1
b = 1
Therefore ,
1/( x + y ) = a = 1/5=> x + y = 5 -( 3)
1/( x - y ) = b = 1/1=> x - y = 1/1 --( 4 )
add equations ( 3 ) and ( 4 ), we get
2x = 5 + 1
2x = 6
x = 3
Substitute x = 3 in equation ( 3 ),
3 + y = 5
y = 5 - 3
y = 2
Therefore ,
x = 3
y = 2
I hope this helps you.
: )
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