solve the problem please
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(x+10)°+(x)°+(x+20)°= 180°
x+10+x+x+20= 180
3x+30= 180
3x= 180-30
3x= 150
x= 150/3
x= 50°
x+10+x+x+20= 180
3x+30= 180
3x= 180-30
3x= 150
x= 150/3
x= 50°
Answered by
1
hiii!!!
here's ur answer...
we know that the total sum of the angles of a line segment is always 180°.
therefore x+10+x+x+20 = 180°
=> 3x+30° = 180°
=> 3x = 180-30
=> 3x = 150°
=> x = 150/3
=> x = 50°
therefore all the angles are :-
→ x+10 = 50+10
= 60°
→ x = 50°
→ x+20
= 50+20
= 70°
VERIFICATION:-
= 60°+50°+70°
= 110°+70°
= 180°
hence verified
hope this helps..!
here's ur answer...
we know that the total sum of the angles of a line segment is always 180°.
therefore x+10+x+x+20 = 180°
=> 3x+30° = 180°
=> 3x = 180-30
=> 3x = 150°
=> x = 150/3
=> x = 50°
therefore all the angles are :-
→ x+10 = 50+10
= 60°
→ x = 50°
→ x+20
= 50+20
= 70°
VERIFICATION:-
= 60°+50°+70°
= 110°+70°
= 180°
hence verified
hope this helps..!
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