Math, asked by abhinav0479, 11 months ago

solve the problems ​

Attachments:

sivaprasath: d0 7
sivaprasath: d) 7
abhinav0479: ha but kase
gautamk2705: I think the answer is -35/4

Answers

Answered by Anonymous
5

Solution :-

Given that ,

 =  > x =  \frac{2}{3 +  \sqrt{7} }

We know that rationalisation factor for 3+ √7 is 3- √7. So , we multiply numerator numerator and denominator by 3- √7 , to get :-

 =  > x =  \frac{2}{3 + \sqrt{7}  }  \times  \frac{3 -  \sqrt{7} }{3 -  \sqrt{7} }

 =  > \frac{2(3 -  \sqrt{7}) }{(3^{2})  - ( \sqrt{7})^{2}  }

 =  >  \frac{2 - 3 \sqrt{7} }{9 -  \sqrt{7} }

 =  > 3 -  \sqrt{7}

Hence ,

 =  > x - 3 =  -  \sqrt{7}

On squaring both sides , we get :-

 =  > (x - 3)^{2}  = 7

Hence , the Value of the given expression is (d).


abhinav0479: thanks
Anonymous: :-))
sivaprasath: 9 - √7 (or) 9 - 7 in 3rd step ??
Anonymous: 9- 7
Anonymous: I will edit it Soon ;)
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