Question

solve the quadratic eqn using factorization
3n^2 -125n + 1300=0

Answer 1

$3 n ^{2} - 125n + 1300 \\ 3n ^{2} - 60n - 65n + 1300 \\ 3n(n - 20) - 65(n - 20) \\ (3n - 65) (n - 20) \\ n = 65 \div 3andn = 20$

Answer 2

3n^2 - 125n + 1300 = 0
using quadratic formula
n = -b-√(b^2-4ac)/2a , -b+√(b^2-4ac)/2a
x = [125-√(15625-15600)]/2×3 , [125+√(15625-15600)]/2×3
n = (125-√25)/6 , (125+√25)/6
n = (125-5)/6 ,( 125+5)/6
n = 120/6 , 130/6
n = 20 , 21.6