Question

Solve the quadratic equation

16 x^2 - 8x + 1

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Answer 1

Hey mate.....✌

Here is ur ans. ⬇


16 x^2 - 8x + 1 = 0

16x^2 - 4x - 4x + 1 = 0

4x(4x - 1) - 1 ( 4x - 1) = 0

(4x - 1) ( 4x -1) = 0

x = 1/4 , 1/4


Therefore the zeroes are 1/4. , 1/4


✌Hope it helps

Answer 2

Hy
Here is your answer
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Q.Solve the quadratic equation

☆16 x² - 8x + 1

Solve:-
$16 {x}^{2} - 4 x - 4x + 1 = 0 \\ 4x(4x - 1) - 1(4x - 1) = 0 \\ ( 4x - 1) (4x - 1) = 0 \\ x = \frac{1}{4}, \frac{1}{4}$
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