Solve the quadratic equation 2ax2 (2a + 3b)x + 3b = 0 by factorisation
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Step-by-step explanation:
2ax² + (2a + 3b)x + 3b = 0
2ax² + 2ax + 3bx + 3b = 0
2ax(x + 1) + 3b(x + 1) = 0
(2ax + 3b) (x + 1) = 0
(2ax+3b)= 0 and (x+1)=0
=>2ax = -3b and x = -1
=>x = -3b/2a
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