Question

solve the quadratic equation for x 4 root 3x2 + 5x - 2 root 3 = 0 .

Answer 1

Solution :

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Given:

To solve for x,

$(4 \sqrt{3}) x^2 + 5x - 2 \sqrt{3} = 0$

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=> $(4 \sqrt{3}) x^2 + 5x - 2 \sqrt{3} = 0$

=> $(4 \sqrt{3}) x^2 + 8x - 3x - 2 \sqrt{3} = 0$

=> $4x (\sqrt{3} x + 2) - \sqrt{3} ( \sqrt{3}x - 2) = 0$

=> $(4x - \sqrt{3}) ( \sqrt{3}x - 2) = 0$

For the equation to be 0,

=> $4x - \sqrt{3} = 0$ (OR) $\sqrt{3}x -2 = 0$

=> 4x = √3 (or) √3 x = 2

=> $x = \frac{ \sqrt{3} }{4}$ (or) $x = \frac{2}{ \sqrt{3} }$

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Answer 2

Hey mate,

Here is the answer....

Hope it is helpful.

Plz mark me brainliest......