Math, asked by mahek7mishra, 7 months ago

Solve the quadratic equation x2+x-20=0

Answers

Answered by bhavanaRS
1

Answer:

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Answered by riyabante2005
2

Step-by-step explanation:

x²+x-20=0

compare equation with ax²+bx+c=0

a=1;b=1;c=20

x²+x-20=0

x²+5x-4x-20=0 product=-20

x(x+5)-4(x+5)=0 sum=1

(x+5)(x-4)=0 no.=5,-4

(x+5)=0 or (x-4)=0

x=-5 or x=4

therefore the root of quadratic equations is -5 and 4

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