solve the quraditic equation 2x²-6x+3=0
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Answer:
2x^2-3x-2x+3=0
X(2x-3)-(2x-3)=0
(2x-3)(x-1)=0
as if p.q=0
=>either p=0 or q=0
so
2x-3=0
=> X=2/3
or. x-1=0
=>X=1
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