Question

solve the simultaneous eqution.. 2x-3y=9 ;2x+3y=3​

Answer 1

2x = 9+3y

x = 9+3y/2

then putting the value of x in 2nd equation

2x+y = 13

2×9+3y/2 + y = 13

9+3y+y = 13

9+4y = 13

4y = 13 - 9

4y = 4

y = 4/4

y = 1

now in equation 2nd

2x + y = 13

now putting y=1

2x + 1 = 13

2x = 13 - 1

2x = 12

x = 12/2

x = 6

Answer 2

2x - 3y = 9 -------------------> (i)

2x + 3y = 3 -------------------> (ii)

From equation (i) and (ii)

2x - 3y = 9

2x + 3y = 3

By elimination method

4x = 12 [-3y and +3y get eliminated]

=> x = 12/4

=> x = 3

Putting the value of x in equation (i)

= 2x - 3y = 9

=> 2×3 - 3y = 9

=> 6 - 3y = 9

=> -3y = 9 - 6

=> -3y = 3

=> y = 3/-3

=> y = -1

Therefore,

x = 3, y = -1

Hope it helps.....

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