Chemistry, asked by unaisabulla754, 10 months ago

What is the % ionic character in hi? Given electronegativity of h = 2.2 and i = 2.6?

Answers

Answered by Anonymous
17

Answer:

Linus Pauling proposed an empirical relationship which relates the percent ionic character in a bond to the electronegativity difference ΔχΔχ.

Percent ionic character =(1−e−(Δχ/2)2)×100=(1−e−(Δχ/2)2)×100

But I'd like to correct the definition of percent ionic character in your question using dipole moment μμ (not Observed value of ionic character):

Percent ionic character = μobservedμcalculatedμobservedμcalculated ×100%×100%

Where μcalculatedμcalculated is calculated assuming a 100% ionic bond.

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