Question

Solve the sum with Quadratic equation

Answer 1

Answer:

$\sqrt{3} \: {x}^{2} + 11x + 6 \sqrt{3} \: x = 0$

$\sqrt{3} \: {x}^{2} + 9x + 2x + 6 \sqrt{3} \: x = 0$

$\sqrt{3} \: x(x + 3 \sqrt{3} ) + 2(x + 3 \sqrt{3} ) \\ = 0$

$(\sqrt{3} \: x+ 2)(x + 3 \sqrt{3} ) = 0$

case 1

$when \\ (\sqrt{3 } \: x + 2) = 0 \\ \sqrt{3} \: x = - 2 \\ x = \frac{ - 2}{ \sqrt{3} } \\ x = \frac{ - 2 \times \sqrt{3} }{ \sqrt{3 \times \sqrt{3} } } \\ x = \frac{ - 2 \sqrt{3} }{3}$

case 2

$when \\ x + 3 \sqrt{3 } = 0 \\ x = - 3 \sqrt{3}$