Question

Solve the system of x+2y+z=3 , 2x+3y+2z=5 , 3x-5y+5z=2 , 3x+9y-z=4

Answer 1

Given :  x+2y+z=3 , 2x+3y+2z=5 , 3x-5y+5z=2 , 3x+9y-z=4

To Find : Solve for x , y and z

Solution:

x+2y+z=3         Eq1

2x+3y+2z=5      Eq2

3x-5y+5z=2      Eq3

3x+9y-z=4      Eq4

Eq1 + Eq2

=> 3x + 5y  + 3z = 8    Eq5

Eq5 - Eq3

=> 10y - 2z  = 6   => 5y  -  z   = 3

Eq5 - Eq4

=> -4y + 4z  = 4  => -y  + z  = 1   =>  z = 1 + y

5y  -  z   = 3 => 5y  - 1 -  y  = 3  => 4y  = 4

=> y = 1

=> z = 1 + y  = 2

y   = 1  , z  = 2

x+2y+z=3   => x + 2 + 2  = 3  => x = - 1

x = - 1 ,  y = 1 , z = 2

Learn More:

Solving system of equation X-2Y=10, 2X-Y-Z=8, -2Y+Z=7 using ...

brainly.in/question/20090447

x+y+z=1,2x+2y+3z=6,x+4y+9z=3,solve the system of equations by ...

brainly.in/question/25808974