Question

solve the x×e^x-2 by regular falsi method upto 4 decimal points​

Answer 1

not understandable

Step-by-step explanation:

please send photos and aks again

Answer 2

Answer:

The formula for regula falsi is as follow:

 

Suppose the root is located between x = a and x = b with a < b

 

then x1 = a -[(b-a) f(a)]/[f(b) - f(a)]

 

Let us suppose that f(a) < 0 and f(b) > 0.

 

f(x1) will be either greater or less than zero (unless you got the root exactly!)

 

if f(x1) < 0, replace a with x1 and f(a) with f(x1) in the formula and repeat the process to get x2

 

if f(x1) > 0, replace b with x1 and f(b) with f(x1) in the formula and repeat the process to get x2

 

I will do the first round for you, then you follow until the 2nd decimal does not change

 

For your problem a = 0 and b = 1

f(0) = -2 and f(1) = .718282

 

x1 = 0 - [1-0](-2)/[.718282-(-2)] = .735759

hope it helps  :)