Math, asked by akhilkumarkota28, 4 months ago

solve the x×e^x-2 by regular falsi method upto 4 decimal points​

Answers

Answered by Anonymous
2

 <marquee behaviour-move> <font color="olive"> <h1>ᴀɴsᴡᴇʀ</ ht> </marquee>

The formula for regula falsi is as follow:

Suppose the root is located between x = a and x = b with a < b

then x1 = a -[(b-a) f(a)]/[f(b) - f(a)]

Let us suppose that f(a) < 0 and f(b) > 0.

f(x1) will be either greater or less than zero (unless you got the root exactly!)

if f(x1) < 0, replace a with x1 and f(a) with f(x1) in the formula and repeat the process to get x2

if f(x1) > 0, replace b with x1 and f(b) with f(x1) in the formula and repeat the process to get x2

I will do the first round for you, then you follow until the 2nd decimal does not change

For your problem a = 0 and b = 1

f(0) = -2 and f(1) = .718282

x1 = 0 - [1-0](-2)/[.718282-(-2)] = .735759

hope it helps :)

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