Question

solve these question​

Answer 1

Answer:

So longer anser 737589055

Answer 2

Hi beautiful

Here is ur answer

1)

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since any +ve odd integer n is of the form 4q+1 or 4q+3

if n=4q+1

squaring both sides

n square=16q2+1+8q

              8(2q2+1q)+1

            8q+1 where q=2q+1

if n=4q+3

squaring both sides

n square=16q2+9+24q

              8(2q2+1+3q)+1

            8q+1 where q=2q2+1+3q

2)

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let 'a' be any positive integer and b=2

By euclid's division algorithm

a=bq+r       0≤r<b

a=2q+r       0≤r<2

(i.e) r =0,1

r=0 , a=2q+0=> a=2q

r=1, a=2q+1

if a is the form of 2m then 'a' is an even integer and positive odd integer is of the form 2m+1

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