solve this :-
(1/sec² theta -cos² theta+1/cosec² theta-sin²Theta)sin² theta cos²theta = 1-sin²theta cos² theta /2+sin²theta cos² theta
Answers
Answered by
10
Step-by-step explanation:
ręfèr tø thę @tt@chmęñt ........
Attachments:
Anonymous:
it's sec²∅ .. not sin
also 1/... ,
Answered by
6
Refer the attachment.
Attachments:
Similar questions