Math, asked by lko, 1 year ago

Solve this..
◻➕◻➕◻➕◻➕◻=30
Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15)
U can also repeat the numbers..This question came in UPSC Final Exams held in Dec '13...... You will be glad to note that only Gaurav Agarwal could solve it.

Answers

Answered by poojan
1
The sum of three odd numbers gives an odd number
So, the sum of 3 given odd numbers doesnt results 30
So, it is an impossible factor
here we can't use 3! too
because 3! [3×2×1] results a even number 6
so we cant use it.
If there will be an allowance of factorials, then the answers will be
3!+1+5+7+11=30
3!+1+3+7+13=30
Answered by kvnmurty
2
Gaurav Agrawal (IAS) answered very intelligently in 2014 using his imagination as 3! + 3! + 3! + 3! + 3! = 30  This question is asked so many times.. all credit goes to him.  The following ways are my suggestions.
I can answer this question in many ways using the factorial function. 
3 ! => 3 factorial. it is a mathematics operator like + or /.. 3 ! = 3 * 2 * 1 = 6.

   3! + 1 + 3 + 9 + 11          = 30
       1 + 5 + 7 + 3! + 11               = 30
             3! + 3! + 3! + 11 + 1             = 30
                 3! + 3! + 11 + 5 + 1               = 30
            11+ 1 + 1 + 3! + 11              = 30
       15 + 3 + 3 + 3 + 3!              = 30
     13 + 1 + 1 + 9 + 3!            = 30
         13 + 1 + 3 + 7 + 3!            = 30
               13 + 5 + 3 + 3 + 3!            = 30

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You need one operator for which the result is an even number with an input being an odd number.  Factorial is one.  Probably there are other operators too.





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