Question

solve this.............

Answer 1

Given ∠PCA = 110° and PC is the tangent.

Given O is the centre of the circle.
Hence points A, O, B and P all lie on the same line.
Join points C and O.
∠BCA = 90° [Since angle in a semi circle is 90°]
Also ∠OCP = 90° [Since radius ⊥ tangent]

From the figure we have, ∠PCA =∠PCO + ∠OCA

That is, 110° = 90° + ∠OCA

Therefore, ∠OCA =20°

In ΔAOC, AO = OC [Radii]

So, ∠OCA = ∠OAC =20°
In ΔABC, we have

∠BCA = 90°, ∠CAB = 20°

Therefore, ∠CBA = 70°

i hope it helps u buddy ✌✌