Question

solve this :9x2-8x-1=0
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Answer 1

$9 {x}^{2} - 8x - 1 = 0 \\ = > 9 {x}^{2} - 9x + x - 1 = 0 \\ = > 9x(x - 1) + 1(x - 1) = 0 \\ = > (x - 1)(9x + 1) = 0$

So,

x = 1

or

x = -1/9