Question

solve this any genius ​

Answer 1

1/(x-3) - 1/(x+5) =1/6

(x+5)-(x-3)/(x-3)(x+5) =1/6

(x+5-x+3)/x^2+5x-3x-15 =1/6

8/x^2+2x-15 =1/6

48 = x^2+2x-15

x^2+2x = 63

x^2+2x-63 = 0

now.. u can find the value of x by shreedharacharya method...

Answer 2

Step-by-step explanation:

1/(x-3) - 1/(x+5) =1/6

(x+5)-(x-3)/(x-3)(x+5) =1/6

(x+5-x+3)/x²+5x-3x-15 =1/6

8/x²+2x-15 =1/6

48 = x²+2x-15

x²+2x-63 = 0

x²+9x-7x-63=0

x(x+9)-7(x+9)=0

(x+9)(x-7)=0

x=-9/x=7

Hope it helps u...

Plz mark it the brainliest answer :)