solve this by substitution method.
11x+15y+23=0
7x-2y-20=0
Answers
Answered by
234
11x + 15y + 23 = 0 ---------------------(1)
7x - 2y - 20 = 0 -------------------(2)
2y = 7x - 20
y = 7x/2 - 10 put in equation (1)
11x + 105x/2 -150 + 23 = 0
127x/2 - 127 = 0
x = 2 put in equation (2)
14 - 2y - 20 = 0
y = -3
7x - 2y - 20 = 0 -------------------(2)
2y = 7x - 20
y = 7x/2 - 10 put in equation (1)
11x + 105x/2 -150 + 23 = 0
127x/2 - 127 = 0
x = 2 put in equation (2)
14 - 2y - 20 = 0
y = -3
Answered by
83
Answer:
x = 2 and y = -3.
Step-by-step explanation:
Given Equation:-
11x + 15y = -23 ......(i)
7x - 2y = 20 ......(ii)
Multyplying (i) by 2 and (ii) by 15 and adding the result, we get
⇒ 22x + 105x = -46 + 300
⇒ 127x = 254
⇒ x = = 2.
Putting x = 2 in eq (i), we get
⇒ 11(2) + 15y = -23
⇒ 22 + 15y = -23
⇒ 15y = -23 - 22
⇒ 15y = -45
⇒ y =
⇒ y = -3.
Hence, x = 2 and y = -3.
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