Question

solve this ...
don't post useless answer......

Answer 1

=[√3+1/√3-1]^2+[√3+1/√3-1×√3-1/√3+1] -- [√3-1/√3+1]^2
=[(√3+1)^2/(√3-1)^2]-[(√3-1)^2/(√3+1)^2]
=[4+2√3/4-2√3]-[4-2√3/4+2√3]
to equalise the bases we need to do LCM after that :-)
=(4+2√3)^2-(4-2√3)^2/16-4√3
=(28+8√3)-(4-8√3)/ 16-4√3
=28-4/ 16-4√3
=24/ 16-4√3
=24/4(4-√3)
=6/4-√3
Hope it helps