Solve this equation by elimination method
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Answer:
Step-by-step explanation:
divide and multiply both the side by 3 in 1st eqution and in second divide and multiply by 5,
so we get,
3x-2y=8--------1st eqution
2x-5y=7-------2nd eqution
so multiply both the side by eqution 1 and 2 by 2 or 5 respective
so we get ,
15x-10y=40 and 4x-10y=14 respectively,
so to eliminate the y we subtract eqution 1 from 2
[15x-10y=40]-[4x-10y=14]
so solving this we get,
x=26/11
so now put this x value on eqution 1st
so we get value of y,
3(26/11)-2y=8
78/11-2y=8
(78/11)-8=2y
78-88/11=2y
-10/11=2y
-10/22=y
y=-10/22
hence value of (x,y)=(26/11,-10/22)
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