Solve this equation by elimination method: x+4y=27 x+2y=21
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Answered by
9
Subtracting both the equations,
x+4y=27
-(x+2y)=-21
____________
2y=6
y=3
putting the value of y from 1
x+4(3)=27
x=27-12
x=15
x+4y=27
-(x+2y)=-21
____________
2y=6
y=3
putting the value of y from 1
x+4(3)=27
x=27-12
x=15
Anonymous:
2y=6 from where it came
sir plz explain
i get it
thanks
sir plzz try to solve with explanation
x+4y - (x+2y) = 27 - 21. therefore x+4y -x-2y =6. Hence we get 2y =6. We subtract equation 2 from 1.
yaa i get it
sir thoda samaj na ma time laga but nyc answer
thanks u teacher
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Answered by
2
x+4y=27
-(x+2y)=-21
2y=6
y=3
putting the value of y from 2
x+4(3)=27
x+12=27
x= 27-12
x = 15
hope it's help u
x=15
-(x+2y)=-21
2y=6
y=3
putting the value of y from 2
x+4(3)=27
x+12=27
x= 27-12
x = 15
hope it's help u
x=15
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