Solve this equation...... x+a/x-a=b-a/b+a
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adityatripathi75:
can you do it clearly because it is unclear
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here is your answer: -
x+a/x-a=b-a/b+a
=> (x+a)(b+a)=(b-a)(x-a)
=> bx+ax+ab+a^2=bx-ab-ax-a^2
=> bx-bx+ax+ax+ab+ab+a^2-a^2 = 0 (bx-bx=0 and a^2-a^2=0)
=> ax+ax+ab+ab = 0 (ax+ax=2ax and ab+ab=2ab)
=> 2ax+2ab =0 (2a taking common)
=>2a(x+b)=0
I hope this helped you so plz rate accordingly
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